Question

EGR 246 STRENGTH OF MATERIALS SUMMER 2020 <CHPT 9 Problem 9.6 Part A Determine the stress components acting on the inclined plane AB in (Figure 1), where Tzy = 8.0 ksi. Solve the problem using the method of equilibrium. Express your answers, separated by a comma, to three significant figures. EVO AE vec ? ksi, ksi Submit Request Answer Provide Feedback Figure 1 of 1 > B 5 ksi 40° 3 ksi

Answer 1

1. 
   imr * Analytical method: [equilibrium method ry A (ACE) 190 с B с facie by BCXL) Tu CS Scanned with CamScanner
   
   Efn=0 Darby Tx in B) Cosg(+ Ty (Bc yigt sino LOSO AB A coso - Tuse) sino Tz costo + Ty sinto (0520 2 ។ Ox (1410510 T. Txt oy ] - Jy (OS20 J :] sing + = - Gz (MB)Q)sino і сис) + Tye jy loso BC (ose AL 7 AB sine + Oy 11 АС De coso sino + ry sing cose sine.it Ty sino - 167) 7 = 2 Je Ty sin 20 て 11 1 CS Scanned with CamScanner
   
   T (ACX ) kryl Bolt) E Fn = 0 (AC)t BC tay (ABX) S960 + Zyx (Bay) ös de = zzy lat.] square + tyle Sing COSE AC yasina coso Tag coso sino t txy sino [rzy TACH +Tay coso (MB)(8) Heyx (BC) tsine Tay AB nc OSO - tyr (BC) sino - てる Tay COS20 CS Scanned with CamScanner
   
   2224 Ty rox -Tj (0520 + Zxy Sinzo - G + L + (© 2-59) sinto † tay c0526 Convention :- VG ve tve CS Scanned with CamScanner
   
   we need Consider Sign Convention for angle B 58 0=500 AA 2409 o is t've A Ois't've 0 =50"' is regivitive given Here = 518i V = 3 ksi Try = 8.0ksi = -50° 8 By substituting values CS Scanned with CamScanner
   
   LOS 20 or + -6] + ("] exy Sine 5 +3 5-3 + (Os 21-50) + 2 2 8 sin 2(-50) + 8 sin (100) SS 4 + I cos(100) 4 + 6 0.1736) + (-7.878) = -4.0516 ksi 10520 Sinzo + tag zdy = -(4) sin 26-50) + 8 (05:50) Exley! 0.9840 + (1.389) Tryl 0.404 Ksi Scanned with CamScanner