a). The differences are
Observation | |
1 | 42.3 - 45.5 = -3.2 |
2 | 47.2 - 46.4 = 0.8 |
3 | 43.6 - 45.7 = -2.1 |
4 | 46.4 - 50.5 = -4.1 |
5 | 47.9 - 50.4 = -2.5 |
6 | 45.6 - 45.7 = -0.1 |
7 | 48.2 - 49.4 = -1.2 |
8 | 49.6 - 49.7 = -0.1 |
b)
c) In order to test this, the correct null and alternate hypothesis are
option C is correct.
The value of the test statistics is
The p-value corresponding to a test statistics of -2.597 and degree of freedom of 7 is 0.018.
Since the p-value is less than the significance level, hence we will reject the null hypothesis.
Result - We will reject the null hypothesis. There is sufficient evidence that at the level of significance.
Option D is correct.
d) The 95% confidence interval around the population mean difference is
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Assume that the differences are normally distributed. Complete parts (a) through (d) below. 1 4 5...
Assume that the differences are normally distributed. Complete parts (a) through (d) below. 1 4 5 7 8 Observation X 2 49.1 3 44.6 6 50.8 46.0 49.8 48.8 46.7 50.0 Y 49.4 47.6 46.8 54.6 50.4 50.4 46.8 52.7 (a) Determine d =X-Y for each pair of data. 1 3 4 5 6 7 8 Observation 2 d; (Type integers or decimals.) (b) Computed and sd- (Round to three decimal places as needed.) Sda (Round to three decimal places...
Assume that the differences are normally distributed. Complete parts (a) through (d) below. 9 Observation X; 1 46.2 47.8 2 54.6 54.3 3 46.0 51.1 4 45.7 50.8 5 42.6 45.2 6 50.4 50.1 7 45.4 49.2 8 45.0 47.6 (a) Determine d; = x; -Y; for each pair of data. Observation 1 2 0 0 (Type integers or decimals.) 3 0 4 0 5 0 6 0 7 0 8 0 (b) Computed and sd. und to three decimal...
11. Assume that the differences are normally distributed. Complete parts (a) through (d) below. Observation 1 2 3 4 5 6 7 8 X 50.1 49.4 50.2 44.1 51.4 51.8 50.6 46.9 Y 53.5 49.3 53.3 48.2 51,2 51.7 54.4 48.5 (a) Determine d = X - Y, for each pair of data. 2 3 4 5 6 7 Observation 1 di (Type integers or decimals.) (b) Computed and sa da (Round to three decimal places as needed.) Sg =...
11. Assume that the differences are normally distributed. Complete parts (a) through (d) below. Observation X Y 1 52.6 53.3 2 52.5 3 44.4 4 44.0 48.4 5 55.1 6 464 7 478 50.5 B 50.4 52.6 51.8 49.5 54.3 49.2 (a) Determine d = XY, for each pair of data. 2 5 6 7 Observation d (Type integers or decimals.) (b) Computed and s. (Round to three decimal places as needed.) Sa (Round to three decimal places as needed.)...
7. Assume that the differences are normally distributed. Complete parts (a) through (d) belovw Observation 1 53.4 49.4 51.7 48.1 49.1 50.6 43.954.0 54.6 48.9 54.4 53.8 49.7 51.3 46.5 53.1 (a) Determine di =Xi-Yi for each pair of data Observation 4 (Type integers or decimals.) (b) Compute d and sd (Round to three decimal places as needed.) (Round to three decimal places as needed.) (c) Test itụd < 0 at the α-0.05 level of significance What are the correct...
Assume that the differences are normally distributed. Complete parts (a) through (d) below Observation 1 2 3 45 678 44.1 52.2 44.5 483 433 516 522438 45.2 537 48.7 534 45.1 548 533459 (a) Determine d X-Y for each pair of data Observation 34567 (Type integers or decimals.) (b) Compute d and sa d(Round to three decimal places as needed) sa Round to three decimal places as needed.) (c) Test if Ha 0 at the a 0.05 level of significance...
1.2. Assume that the differences are normally distributed. Complete parts (a) through (d) below. 1 3 4 6 8 Observation X 2 53.4 5 49.0 7 46.1 43.3 46.2 42.4 51.4 51.7 46.9 52.9 48.8 47.3 51.9 54.8 46.7 52.6 - 2.6 - 4.9 - 2.9 -3.4 -0.6 -.9 d; -3.6 .5 (Type integers or decimals.) (b) Computed and sd d = -2.300 (Round to three decimal places as needed.) Sa = 1.805 (Round to three decimal places as needed.)...
19 25 The sample of six measurements shown below was randomly selected from a normally distributed population. Complete parts a through c. 1,2,3,3,4,1 a. Test the null hypothesis that the mean of the population is 3 against the alternative hypothesis. p < 3. Use a = 0.05 Ifq=0.05, find the rejection region for the test. Choose the correct answer below. % 1994 1994 OA. <-2015 or t> 2015 Oct-2571 O E. > 2571 OB < -2015 OD < -2571 ort...
14. Use the following information to complete steps (a) through (d) below. A random sample of n = 135 individuals results in x1 = 40 successes. An independent sample of n2 = 140 individuals results in X2 = 60 successes. Does this represent sufficient evidence to conclude that p1 <P2 at the a=0.05 level of significance? (a) What type of test should be used? O A. A hypothesis test regarding the difference between two population proportions from independent samples. OB....
Use the following information to complete steps (a) through (d) below. A random sample of ny = 135 individuals results in xy = 40 successes. An independent sample of n2 = 150 individuals results in x2 = 60 successes. Does this represent sufficient evidence to conclude that P, <P2 at the a = 0.10 level of significance? (a) What type of test should be used? A. A hypothesis test regarding the difference between two population proportions from independent samples. B....