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Consider the figure below. (Due to the nature of this problem, do not use rounded intermediate values in your calculations-In
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9 = 16.1MP C₂ = sy.4 MF C3 = 34.9 MF V=NAB д. 4 V C2 Now, 63 and ca) 1.77 th 4, C2 are in Parallel. Eanivalent capacitance, o(d) stored stored energy in each capacitor- Ź x 16.1 x 1.772 E = G12 I AJ Ei = 25.22 X 10^6 J Ez s v2 Í ez v2 - 4x94.4x10-6 x

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