Question

--- 4) A particular irreversible chemical reaction follows the rate law ratek [A] At a particular temperature the value for the rate constant is k - 3.78 x 10-*s! a) In an experiment carried out at that temperature the initial concentration of A in a system is [A]o - 8.35 x 102M. What will the concentration of A be in the system att - 500.s? (8 points)

Answer 1

Answer:

Auswen Rate=k. [A at is a 1st onden reaction. K = 3.78x10-48-) Ao initial csue. For 1st onder reaction Az Ao e te time on kz Rate const. - kt 12 final al cone

+ 500s. Now Ao = 8.35 x 102(M) k z 3.788 10-487 kt A = Aoie or, A = (8.35x10-2). e (3.78 x1049.500 : 0.069 12 Mono 6.912x 10-2 (M) " Cove of A in the systems at t= 5008 is 6.912 x 10-2 (M) Aus by From Arhienious equation we know ak= A e EART or, luk= hu A - Ea/RT forluk vsk Y= slope Fair z ture te m= -7.54 Slope and Ay from graph -9.0 -7.5 -1-9-09) 0.00335-0.00310 1. 6000 2.5*10-4 Ea/R = 6000 ano Ea = - 6000* 18.314h not ! - 49884J Any 0.00310 0.00335