Answer is C - 110GPa
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16.) There is a composite material that is us% resin Lyoung's modulus of 7.6 GPa) and...
Q4
Acomposite consists of 65% polyester resin is reinforced by continuous and aligned glass fibers. The modulus elasticity of hardened resin is 4 0 GPa and the modulus elasticity of the ibers la 52.0 GPa. Compute: a. The overall modulus elasticity of composite in the longitudinal direction parallel 04. to fiber direction b. The load carried by each matrix and iber phase, If uniaxial srss of 50 MPa is applied in longitudinal direction on the 250 mm2 cross-sectional area. c....
A composite of polycrystalline spinel (Young's modulus = 277 GPa) and aligned continuous Kevlar fibers is desired in order to increase the capacity of the spinel to withstand impact. Kevlar fibers have a tensile strength of 3.6 GPa and a Young's modulus of 125 GPa. For a desired composite with Young's modulus of 200 GPa, what is the fiber volume fraction? Use isostrain condition.
Calculate the modulus of elasticity for a composite material consisting of 60 percent by volume of continuous E-glass fiber and 40 percent epoxy resin for the matrix when stressed under isostress conditions. The modulus of elasticity of the E glass is 72.4 GPa and that of the epoxy resin is 3.1GPa.
A composite material of graphite-filled nylon is designed with a mixture of 65% of graphite by volume. Given the densities of the consituent materials below: Material Density (8 cm) Young's modulus, E (pa) Graphite 1.75 224 Nylon 1.36 2.5 a) Calculate the density (Protal of the resultant composite material to two decimal places. Profal = 1.59 8 cm3 b) What is the weight fraction of nylon to 2 decimal places? 0.40 % c) What is the Young's modulus (E) of...
Use Halpin-Tsai. A composite is made of unidirectionally aligned carbon fibers in a glass-ceramic matrix. The following data are available: Ef1 = 280 GPa, Ef2 = 40 GPa, Em = 70 GPa, νf1 = 0.2, νm = 0.3, Gf12 = 18 GPa a. Compute the elastic modulus in the longitudinal and transverse directions. b. Compute the two Poisson’s ratios. c. Compute the principal shear modulus, G12.
In an aligned and continuous carbon fiber-reinforced nylon 6,6 composite, the fibers are to carry 94 % of a load applied in the longitudinal direction. Modulus of Elasticity [GPa(psi)] Tensile Strength [MPa(psi)] Carbon fiber 260 (37 ×106) 4000 (5.8 ×105) Nylon 6,6 2.8 (4.0 ×105) 76 (11,000) (a) Using the data provided, determine the volume fraction of fibers that will be required. (b) What will be the tensile strength of this composite? Assume that the matrix stress at fiber failure...
Question B4 Carbon fibres typically have a modulus of 230 GPA, a tensile strength of 3.8 GPa and a density of 1.78 g cm3. In making composites, carbon fibres are often used with epoxy matrices that have a modulus of 3.0 GPa, a tensile strength of 60 MPa and a density of 1.3 g cm3. Which of the following is incorrect? (a) A carbon fibre/epoxy composite containing randomly oriented carbon fibres will have a lower modulus than one containing a...
Problem 8 10 pts) A continuous and aligned fiber-reinforced composite part has cross sectional area of 300 mm2 and consists of35 vol% glass fibers and 65 vol% of a nylon 6,6 matrix. If a longitudinal tensile load of 50kN is applied to the composite, determine (a) the longitudinal modulus of elasticity of the composite, (b) the longitudinal strain in the composite, (c) the stress in each phase (fiber and matrix), and (d) the magnitude of the load carried by each...
2. Composites Rules of Mixtures Review Problem A fiberglass composite consists of a matrix of vinyl ester and reinforcement of E-glass. The volume fraction of E- glass-3000. The density of the vinyl ester 0.882 g/cm and its modulus of elasticity: 3.60 GPa. The density of E- glass 2.60 g/cm, and its modulus of elasticity . 76.0 GPa A section of composite 1.00 cm x 25.00 cm x 200.00 cm is fabricated with the E-glass fibers running longitudinal in the 200-cm...
Typical Vickers indentation on a 4 vol% carbon nanotube (CNT) reinforced ZrB2 ceramic composite shows cracks emanating from the indentation corners (see figure). The indentation was obtained using load of 1000 g and holding time of 15 s (Vickers Hardness tester). Fracture toughness and Hardness of material are given by expressions: 1/2 0.016(5) H/2 1.854P where E is Young's Modulus of the composite (GPa); H is Vickers Hardness (GPa); P is applied load (N); c is diagonal crack length emanating...