Question

The figure below shows a 50 cm long bar attached to ideal frictionless parallel wires. The bar is free to slide along the wires but its orientation is forced by the attachments. The bar is pulled by an external force at a constant velocity along the wires in the presence of a B - 3.10 T magnetic field which points into the screen. The parallel wires are connected to a R-28.01 resistor and the bar makes an angle of @= 30 with the wires. A 1.0.10 A induced current is measured in the resistor labeled R. The bar itself has a resistance = 5.0 and a diameter of 1.1 cm. M R K X X 0 x

Answer 1

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# I K SO L 0.5m diameter B = 3.1 T da 0.011 m R - 2822 Area A - IT = 30 I= 0.1A A = 3.14 xl 0.0m)? - 5 2 4 A) Magnetic force A = 9.5 x10-5m Fo= ILB 0.1X0.5 * 3.1 Fo= 0.155 N B) Due to Que to motion of motion of bar, flux is increasing Current I is induced in anticlock wise direction to decrease the Fluk. c) Emf 8 F(RU) = 0.1(28+5) 3.3 volt E = UBL sin 30' E 3.3 = x 3.1 x 0.5 1x 0.5% ►us 4.26 mis D) Resistance of bar Resistivity Pa TA S = 5 x 9.5xios, 9.5x104 лм 0.5 r=ph