Question

Evaluate the integrals. 3x2 - 4x+7 dx (x2–2)2

Answer 1

8x24x47 dx Q-2)2 By finding partial fractions dx 3u-uxti da + 13.ua 222 (a?-2.72 (2-2) da 3 35 de-/ 42-13 (12-22 S dr da 00) (-A) Vetrec = 2312) Tarix - 12/31 ) entrada 2012 en (8-12) - 12 3 12 dn(x+2) - Now solving shox -42 @=-272 2) da =Sassjon - (20) fathi dz Jazh 2 (222) da -12)XX+0212 da + to di later 8 Jatrat Jatt en(x-12) stupiment 123 22 8 (2412) 56)

By combining all we get =.-3 ln(2402) +13 Inca + 02) 3ln11-12) + ) – 130119-62) 2312 2 4/2 Q²h2 2 412 + -13 -13 8(2402) 817-12) .c In(atr)-da (2-2) + 8-132 tc 4 (2²2) 2 412