Question

Please answer with work

Evaluate the limit. sin 5x 10) lim 10) X>0 sinx A) -5 B) 1 C) 5 D) 0

Answer 1

please comment if you have any doubts will clarify

-اهی Given tim Sin 5x X0 Sina If we put azo we get which is in determinate form. So Let's apply LHopital's rule. lim Sinsa 970 Sina 830 lim alda (sin5x) fda (Sine) 7 lim 5 Cos 5x [ (sto nx) e aceae 820 Cosa D. 5 cos (500)) coslo) 510. Cos (0) -1 -1] 5 - lim 270 Sin sa Sina 5