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Find an equation for the line tangent to the curve at the point defined by the given value oft. Also, find the value of dy at
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Answer #1

Solution, N=++ cost Y = B densint, It 2 Sint t=16 da d (t + cost) dt dt - I-Sint dy dt =후 1+25int) dt 2 cost dy da = 1 dyldtCompute the first derivative and use these to Compute dylda (k) - ㅠ 6 + Cos( le) ㅠ t J3 2 T十33 G =1425in(E ST) - 1+2() C2 dy9-2= 253 (x- (T + 35 9-22 1522 - bus + 9-2= 2530-/2153 + 18 + 2 ya 12131 - 2153-18 6 y= 12532-21553 -18712 6 2 y = 12530 125

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