d²y Find an equation for the line tangent to the curve at the point defined by...
Find an equation for the line tangent to the curve at the point defined by the given value of t. Also, find the value of at this point x=16 cost, y = 4 sint,t= The equation represents the line tangent to the curve at t= (Type an exact answer, using radicals as needed.) d²y The value of dx2 (Type an exact answer, using radicals as needed.) att =
Find an equation for the line tangent to the curve at the point defined by the given value oft. Also, find the value of dy at this point x=++ cost, y = 1 + 2 sin tt-7 Write the equation of the tangent line. y=-x+ (Type exact ahswers, using as needed)
11.2.11 Find an equation for the line tangent to the curve at the point defined by the given value of t. Also, find the value of at this point. x=t-sin ty=1 - 3 cos tt Write the equation of the tangent line. y= x+ (Type exact answers, using a as needed.)
Find an equation of the line tangent to the curve at the point corresponding to the given value of t. 71 x= cost+t sint, y=sint-tcost;t=4 (Type an equation. Simplify your answer. Type your answer in slope-intercept form. Type an exact answer. Use integers or fractions for any numbers in the equation.)
Find an equation for the line tangent to the curve at the point defined by the given value of t. 2= sint, y=6 sint, t= 7T 3 Oy=62-63 o V3 y=6x + Oy=63 Oy=-62 +63
Find an equation for the line tangent to the given curve at the point defined by the given value of t. Also, find d2y/dx2 at this point: x = cost, y = 1 + sint, t = 1/2
(1) Find an curve equation for the live tangent to the at the point defined by the giver value of t. Also find value of dry/dx² dy/dx² at this point. a) x = ㅗ y = t t-t t = 2 ttt
Find an equation for the line tangent to the curve at the point defined by the given value of t. x = sin t, y = 2 sin t, t = wa y = 2x - 213 y = 2x y = 2x + 13 Oy=-2x+ 2/3 Find an equation for the line tangent to the curve at the point defined by the given value of t. x=t, y= V2t, t = 18 y=- X-3 y=+x+3 O y = 1...
QUESTION 3 Find an equation for the line tangent to the curve at the point defined by the given value of t. x = 6t2 3y = t2= 1 o y = 1 / 8x + 1 / 2 Oy=}x+1 o y = 2/X 2/2 o y = 6x - 1 / 1
The curve shown below is called a Bowditch curve or Lissajous figure. Find the point in the interior of the first to the curve is horizontal, and ind the equations of the two tangents at the origin. What is the point in the interior of the frst quadrant where the tangent to the curve is horizonta? an ordered pair. Type an exact answer, using radicals as needed ) What is the equation of the tangent at the origin when t...