1
Let's rewrite the given circuit with polarity of current through resistors.
Let's assume right hand side loop is mesh-2 and left hand side loop is mesh-1.
We can see in mesh-2 mesh current is flowing I2 in clockwise direction and the source current Is is not sharing with any other mesh flowing opposite to I2 . Since in a wire there can be only one current therefore
Now apply KVL for mesh-1 we get
Put the given values we get
Now the current through resistor is
Therefore potential
therefore answer to first question is I1=0.5mA and I2=-1.0mA and potential V1=1.5V.
.2
Now here in this problem since source current is sharing with two mesh so can not solve as we did in previous problem. So what we do here let's consider the potential across source current is vs
Then we apply KVL in the three loops.
Mesh-1
For Mesh-2
For mesh-3
Add equation (2) and (3) we get
Now consider the source current and apply the Kirchhoff's current law at the highlighted node. We get
Put this value of Ι3 in equation (1) and (4) we get respectively.
And
Let's first put the values of resistance in equation (6) and (7) remember 1k-ohm=1000 ohm
From (6)
And from (7)
Solve equation (8) and (9) we get
And
Put values in equation (5) we get
Now
And
And
Hence we have found all quantities.
please solve these 2 problems. I will rate you up In the circuit shown below, let...
please answer both problems in detailed solution. I will rate you up In the circuit shown below, let Isi = 2 mA, I2 = 3 mA, RI = 2.5 k 2, R2 = 6 k2, R3 = 4 k. Use nodal analysis to find V and V2. V2 R2 w ska + Is2 Is 1 12mA V1 V2 R3 318 R1 32.5KN w akin . Is = 2 mA , Vs - 6 V , R = 1.5 k 2...
please solve in details. i will rate you up ! Problem 3 In the circuit shown below: a. Write a node equation at node 1 by summing the currents leaving node 1. b. Write a node equation at node 2 by summing the currents leaving node 2. c. Find V, and V2 by solving the two node equations. d. Find the currents IR, IR, IR3, IR4, Is. e. Find the power absorbed by R1, R2, R3, R4, and power released...
How do I solve this ? 2. [15 points] For a circuit below, find Voltages and Currents on R1, R2, R3, R4, R5 and R6. Use either Nodal or Mesh Analysis to solve the circuit. Why you choose Nodal or Mesh Analysis? Vi = 20V, V3 = 20V, R;= 1.0 k1, R= 1.2 k1, R;= 4.1 kN, R = 4.1 kN, R=4.2 kN, R=0.5 k12. R3 R1 R4 V1 V2 HE Hilt R2 R5 R6
Using mesh analysis, solve the following circuit and calculate the current through Ri and the voltage at V relative to ground, given: Vi = 10 V, V2 = 6V, V3 = 2V, R1 = 1k02, R2 = 2 k2, R3 = 3kQ, R = 4k, and Rs = 5k12 V3 7 Ri Rs AN Using mesh analysis, solve the following circuit and calculate the current through R1 and the voltage at V relative to ground, given: V1 = 10 V,...
Is = 2 mA , V , = 6 V , Ri = 1.5 k 2 , R2 = 2 k2 , R3 = 6k02 , R4 = 2.5 k - 2 , Rs = 3 k12 . In the circuit shown below, let Use nodal analysis to find V and V2 R1 1,5kn VI V va R2 w 2 R3 w 6kA + Vs Is V1 R4 V2 R5 WW 6v 2,5kn 3lk / 2 MA
Assuming an ideal op-amp in the following circuit, find output voltage, Vo if R1= 2 K2, R2=8 K12, R3=3.8 KS2, R4=6 KI2, R5=15 KS2, R6=3.8 KN, RL=9.8 K12, V1=1V, 12=0.5 mA and V3=2.2 V. } R6 R1 w R5 w + Vo + } RL 12 R2 V1 R3 R4 + +1 V3 Using the above circuit, but consider the following component values: R1= 2 KN R2=8 K2, R3=4.1 K12, R4=6 KI2, R5=17.0 K12, R6=15 KI, RL=10 KI, V1=1V, 12=0.5mA...
In this circuit, the source voltage is VS = 25 V, and the resistances are: R1 = 10 kΩ, R2 = 18 kΩ, R3 = 2 kΩ, R4 = 20 kΩ. Using the mesh current method, find the mesh currents Ia and Ib (polarities as marked). In this circuit, the source voltage is Vs = 25 V, and the resistances are: R1 = 10 k 2, R2 = 18 k22, R3 = 2 k.22, R4 = 20 k 2. Using...
Assuming an ideal op-amp in the following circuit, find output voltage, Vo if R1= 2 KS, R2=8 KN, R3=3.4 KA, R4=6 KN, R5=20 KN, R6=2.9 KN, RL=12.5 KN, V1=1V, 12=0.5 mA and V3=3.1 V. R6 R1 R5 VO + RL 12 R2 V1 R3 { R4 w V3 Answer: "V
Assuming an ideal op-amp in the following circuit, find output voltage, Vo if R1= 2 K2, R2=8 K2, R3=5.1 K2, R4=6 KN, R5=14 KN, R6=4.2 KS, RL=10.3 KS, V1=1V, 12=0.5 mA and V3=3.2 V. R6 R1 R5 Vo w + * RL + 12 R2 V1 R3 R4 V3 Answer: OV Using the above circuit, but consider the following component values: R1= 2 K12 R2=8 K2, R3=2.9 K2, R4=6 KI2, R5=10.8 K92, R6=15 KO, RL=10 K2, V1=1V, 12=0.5mA and V3=2V....
Include work. Calculate each of the circuit parameters for the provided circuit. RT(K) = Is(mA) = V1(V) = PR1(MW) = V2(V) = PR2(mW) = 11(mA) = 12(mA) 13(mA) = 14(MA) = V3(V) = PR3(mW) = PR4(mW) = V4(V)= V5(V) = PE(MW) = 15(MA) = PR5(mW) = + V1 - 11 w + V3 - 13 R (50) R3 (30) 12 + E = 40V R2(10km) V2 R4(62) 314 14 Is Rs(1ko) Vs+