Question

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The following reaction will not proceed as written. Clearly explain why this reaction will not occur. 1. LDA ix 2. Br

Answer 1

*0mm (step-1) (Enolate) attack) (Not formed) (step-T) from mechanism at is clear that tst enolate will form, which is one nucleophile. Now, alkyl bromide in electrophile. Now, step-II În sp2 reaction. Beat the electrophile(tert- butyl-bromide) in tertiary, bromide and due to steric effect this SN2 recaction is not possilite. so, as step-II in not possible to their reaction will not happer. tBr = 3° aikyl bromide, Storce, SN2 not possible. 0 CH₃cl ". ohlas (Chelation ALAI3 happena As we know that thün in friedle-Craft alkylation. Now for the reaction Ist CH301 and Alc13 react each other to form CH₃ and Alche. But here due to foresence of oxygen of acetophenone, de AlCl3 will clielate with oxyger and she that's wly alkylation reaction, not forsare happened. CHAại axeta X> CH3 - Rels > Ag+ Ret This reaction mot formed. Imotead of AlCl3 Chelate with acetophenone,