Question

The basketball pole ABC is fixed at A and is subject to a force Pas indicated below. The circular cross-section has outer diameter do = 81 mm and inner diameter di = 41 mm. Assume a = 677 mm, L= 2902 mm, P = 820 N, 0 = 62° and b = 580 mm. B 2 D y Determine the state of stress at point D: evaluate the stresses (remember to use sign convention) and draw the representative stress element. -X Stress components: T у Delete button: y D x Matlab input: a = 677; b = 580; L = 2902; do = 81; di = 41; P = 820; theta = 62; kPa Oy = kPa Tag = kPa

Answer 1

90=0 (due to Mz) Pun (63) di-qtmๆ a=677mm op b= 2902 mm 62 7 Pacoxbi) P=820N b-s somn 29=0 WWIB 385N 724.01 ng Μ, -άκρκοι) =679* 820 X WS(61) XV ME 260.62 Wing to 724-DIN Faxper0-260-62 Nim M = M, + m2 - 260.62 +(2902-880)x 724.01 q A tti16) = W M = 1941.77 N.M o at D due to M2 2194677 N.M! 'D' point panes through the į avis o at ' due to point load = 0.093 mpa (composenion) 385 "х Area T/ (812 up) F-724.01 N shear stren due to 724.01x385433 Iz = 1 ou von To = Izt 1974341.75 X40 Ra (04-04 24 (1814-4") T= 197434/195 mmol Fu xog 70.3533 mpa), 0.093 mpa 140-3533mpa H enfreak 39) - 4.4)*5) * claugos) - Of Costa 4x20.5 OT=4[77686.66)mm = 38543.3 mm 34 3