Which equilibrium constant expression represents the first ionization of H3PO4 in water?
Which equilibrium constant expression represents the first ionization of H3PO4 in water?
Which equilibrium constant expression represents the first ionization of H3PO4 in water? A) [H+][H2PO4-]/[H3PO4] B) [H+][PO43-]/[HPO42-] C) [H+][PO42-]/[H2PO4-] D) [H+][H3PO43-]/[H3PO4] E) [H+][H3PO4]/[H3PO4]
The equilibrium constant for an acid is called the acid-ionization constant, Kg. Which Ką value represents the strongest acid? Select one: O Ka = 9.5x10-3 0 Kg = 9.6x10-4 O Ka = 9.7x10-5 O Kg = 9.8x10-6
a. Write the reaction for a monoprotic acid HA with water and its equilibrium constant expression (K) b. Write the reaction for the conjugate base of HA with water and its equilibrium constant expression (Kb) c. Write the reaction for the auto-ionization of water and its equilibrium constant expression (Kw) d. Use the equilibrium expressions for Ka and Ko to prove that K Kb = Kw. What is the physical significance of the KaKb = Kw relationship?
Which of the following equilibria represents the second ionization step of H3PO4? Group of answer choices HPO42-(aq) + H2O(aq) PO43-(aq) + H3O+(aq) H3PO4(aq) + 3H2O(l) PO43-(aq) + 3H3O+(aq) H2PO4-(aq) + H2O(l) HPO42-(aq) + H3O+(aq) H3PO4(aq) + 2H2O(l) HPO42-(aq) + 2H3O+(aq) H3PO4(aq) + H2O(l) H2PO4-(aq) + H3O+(aq)
Write the equilibrium constant for the dissociation of water. Rewrite it in terms of the ionization of water constant Kw. The concentration of hydronium and hydroxide equals what value?
The value of the equilibrium constant for the following chemical reaction (the auto-ionization of water) is 1.0x10-14 at 298 K. 2H2O(l) ßà OH-(aq) + H3O+(aq) K = 1.0x10-14 Using this information and your equilibrium identities, select the correct value for the equilibrium expression for the following chemical reaction (at 298 K as well): 6H2O(l) ßà 3OH-(aq) + 3H3O+(aq) K = ? Question 5 options: 1x1014 1x10-28 1x10-14 1x10-42 3x10-14 1x10-15
The value for the equilibrium constant for the following chemical reaction, the auto-ionization of water, is 1.0x10-14 at 298 K 2H2O(l) ßà OH-(aq) + H3O+(aq) K = 1.0x10-14 Using this information and your equilibrium identities, select the correct value for the equilibrium expression for the reaction shown below (at 298 K as well) : OH-(aq) + H3O+(aq) ßà 2H2O(l) K = ? Question 4 options: 1x10-14 0.5x10-14 2x10-14 -1x10-14 1x1014 1x10-15
Write the equations that represent the first and third ionization steps for phosphoric acid (H3PO4) in water (Use H3O* instead of H.) first ionization step H20( (aq) (s) third ionizatio (g) H20( Submit Answer Retry Entire Group 9 more group attempts remaining +
Write a Ka (acid ionization equilibrium constant expression) for HF according to the following equation: HI (aq) <---------> H+ (aq) + I- (aq) Ka =
Write the equilibrium constant expression, Ka, for the ionization of acetic acid, HC2H302 U ka ka = [HAC] [H20] [H+] [Ac-] Ore - [HAC] [H+] [Ac-] a = [H+] [Ac-] [HAC] [H20] [H+] [Ac-] ka = ! [HAc]