The value for the equilibrium constant for the following chemical reaction, the auto-ionization of water, is 1.0x10-14 at 298 K
2H2O(l) ßà OH-(aq) + H3O+(aq) K = 1.0x10-14
Using this information and your equilibrium identities, select the correct value for the equilibrium expression for the reaction shown below (at 298 K as well) :
OH-(aq) + H3O+(aq) ßà 2H2O(l) K = ?
Question 4 options:
1x10-14 |
|
0.5x10-14 |
|
2x10-14 |
|
-1x10-14 |
|
1x1014 |
|
1x10-15 |
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The value for the equilibrium constant for the following chemical reaction, the auto-ionization of water, is...
The value of the equilibrium constant for the following chemical reaction (the auto-ionization of water) is 1.0x10-14 at 298 K. 2H2O(l) ßà OH-(aq) + H3O+(aq) K = 1.0x10-14 Using this information and your equilibrium identities, select the correct value for the equilibrium expression for the following chemical reaction (at 298 K as well): 6H2O(l) ßà 3OH-(aq) + 3H3O+(aq) K = ? Question 5 options: 1x1014 1x10-28 1x10-14 1x10-42 3x10-14 1x10-15
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