Question

1. Write the chemical reaction for the autoionization of water (equilibrium constant Kw).

2. Look up the numerical value for Kw at Tinitial (Use the average of Tinitial from both trials) -Its 6.81x10^-15

3. How is the equation in Question 1 related to the net ionic equation for the strong acid-strong base neutralization shown below?

   H3O+(aq) + OH-(aq) → H2O(l) + H2O(l)

4. Use the value of Kw and the relationship between the equations in Questions 1 and 3 to find the numerical value

   of K for the neutralization reaction in question 3.

5. Use the value of K calculated for the neutralization reaction in Question 4 to calculate ΔG for the neutralization reaction. (Use average Tinitial from the two trials as the value of T.)

6. Use the values of ΔG and ΔHn that you have already calculated to calculate ΔS° for the reaction. (Use average Tinitial from the two trials as the value of T.)

Answer 1

Chemical reaction for autoionization of water, H₂O(l) + H₂O(l) H₂O + (aq) + OH (94) Kw = 6.81810-15 = [H₂0 tags] [ot cons] Net ionic equation for strong acid - strong base neutralization 4₃0 + (aq) + OH(aq) - Holl) + H₂O4) K for neutralization reaction = -1 [1₂0 cowok K=1.4781014 - 6-81Xior15 Kw AG = - RTink = 1.468428781x10 I 1-47 X1014 = -8.3/4 x 298 xen11.468428781x10!4) (Ilmol-K) = -80819.3507 ) mol = -80.8193509 KJ) mol = -80.8 kJ/mol AG = - 80.8 kJ/mol AS - 44 - AGO - T