Sr(OH)2 (s) ----------> Sr2+ (aq) + 2OH- (aq)
Concentration of Sr(OH)2 = 0.417 M
Concentration of OH- = 2 × 0.417M
= 0.834M
[OH- ] = 0.834 M
pOH = - log (OH- )
= - log ( 0.834) = 0.078
pH + pOH = 14
pH = 14- 0.078 = 13.92
Question 24 1 pts Calculate the pH of a 0.417 M solution of Sr(OH)2. Remember that...
Question 24 1 pts Calculate the pH of a 0.236 M solution of Sr(OH)2 Remember that a pH with three decimal places has three significant figures. Make sure to enter your answer with three decimal places. Question 25 1 pts Determine the pH at the equivalence point of a titration between 50.0 mL of 0.133 M (CH3)2NH solution with 0.133 MHCIO4. Remember that only the decimals in a pH count as significant figures. Please enter your answer with three decimal...
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