Question 12 1 pts Calculate the pH of a solution obtained by mixing 60.79 mL of...

Question

Question

Question 12 1 pts Calculate the pH of a solution obtained by mixing 60.79 mL of 0.11 M CH3COOH with 12.47 mL of 0.12 M NaOH.

Answer 1

Answer #1

The initial moles of acid and moles of NaOH added are calculated:

n Acid = M * V = 0.11 M * 0.06079 L = 0.0067 mol

n NaOH = 0.12 M * 0.01247 L = 0.0015 mol

The NaOH reacts with the acid and forms a conjugated salt, the remaining moles of acid are calculated:

n Remaining acid = 0.0067 - 0.0015 = 0.0052 mol

The pH is calculated:

pH = - log Ka + log (n Salt / n Acid) = - log 1.8x10 ^ -5 + log (0.0015 / 0.0052) = 4.20

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Answer 2

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