Question

12. (-/2 points) DETAILS SERCP11 9.A.P.088. MY NOTES ASK YOUR TEACHER A U-tube open at both ends is partially filled with water (Figure (a)). Oil (p = 750 kg/m?) is then poured into the right arm and forms a column L = 4.43 cm high (Figure (b)). P Shield U Water Oil (a) Determine the difference h in the heights of the two liquid surfaces. (The density of water is 1.00 x 103 kg/m3.) cm (b) The right arm is then shielded from any air motion while air is blown across the top of the left arm until the surfaces of the two liquids are at the same height (Figure (c)). Determine the speed of the air being blown across the left arm. Assume the density of air is 1.29 kg/m² m/s

Answer 1

Solution - Given data e = 750 kg/m3 LE4:43 cm ^) e = 1X103 kg/m3. water Pressure at A Al is equal in both Column's. water A PA = Pot Swo (l-h) PB = Po & ScilgL PA = PB for sus g (1-2) = 8b+ Seit ge Soilgh sugl - Swigh Sruth - Suff - Song (So-So;)) (1X203 - 750) 4:43 1.1675 cm Sw 1x 103 h= 1. 1075 cm d. shika b) Pair = 1.29 kg/m3. pressure difference of height his Compensated by pressure due to flow of air 1/2 ir v² = swigh v2 2 svegli SO sair zsugh 2x103 x 10X1-1075 vo v Sair V 1.29 VE 131.03 m/s) 131-03 m/s