My Notes Ask Your Teacher SerCP11 9.A.P.081. 13. -/1 points The approximate inside diameter of the...

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Answer 1

Answer #1

discharge through aorta

D1 = velocity * area

D1 = 1 * 3.14* 0.0024^2 = 1.81* 10^-5 m^3/s

discharge through capillary

D2 = 10^-2 * 3.14* ( 5.5* 10^-6)^2 = 9.5 m^3/s

now

N D2 = D1

N = 1.906* 10^7

====

Answer 2

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