5. -/2 points SerCP11 16.A.P.063.MI. My Notes Ask Your Teacher A parallel-plate capacitor is constructed using...
A parallel-plate capacitor is constructed using a dielectric material whose dielectric constant is 2.10 and whose dielectric strength is 2.20 108 V/m. The desired capacitance is 0.400 µF, and the capacitor must withstand a maximum potential difference of 4.00 kV. Find the minimum area of the capacitor plates.
A parallel plate capacitor is constructed using a dielectric material with dielectric constant of 3 and whose dielectric strength is 2x10^8 V/m. the desired capacitance is 0.250 mF, and the capacitors must withstand a maximum potential difference of 4 kV. Find the minimum area of the capacitor plates.
8. 3 points My Notes Ask Your Teacher The plates of a parallel-plate capacitor each have an area of 0.1 m2 and are separated by a 0.7 mm thick layer of rubber. The capacitor is connected to a 13 V battery. (The dielectric constant for rubber is 7.) (a) Find the capacitance (b) Find the charge stored (e) Find the electric field between the plates.
17 My Notes Ask Your T -3 points SerCP11 16.P.053 voltage across an air-filled parallel-plate capacitor is measured to be 237.0 V. When a dielectric is inserted and completely fills the space ween the plates, as in the figure below, the voltage drops to V2-69.7 V Deleci ? (a) What is the dielectric constant of the inserted material? Can you identify the dielectric? bakelite o neoprene rubber o paper O nylon o teflon (b) If the dielectric doesn't completely fill...
+ -/5 points SerPSET9 26.P.047 8 +Ask Your Teacher My Notes A parallel-plate capacitor in air has a plate separation of 1.63 cm and a plate area of 25.0 cm2. The plates are charged to a potential difference of 225 V and disconnected from the source. The capacitor is then immersed in distilled water. ASsume the liquid is an insulator. (a) Determine the charge on the plates before and after immersion. рС before after РС (b) Determine the capacitance and...
[A a, 5 5. Determine the capacitance of a parallel plate capacitor using quartz as the dielectric that can withstand a maximum potential difference of 2000 V just before it breaks down. The plate area of the capacitor is 16 cm2, the dielectric constant of quartz is 3.78, and the dielectric strength of quartz is 8x106 V/m. Potenhal differente - 200DV Plat arca: eum2 A) 1.0nF B) 2.0 pF 0.21 nF 0.18 nF 10.0 pF D) E) Dicectne cunstant. 3.1...
Problem 5 (16 +8 Points) A parallel plate capacitor biased under a constant voltage Vo is shown in the figure below. Two parallel plates are separated by a distance of d and filled with a medium whose permittivity is ε,-ε-The parallel plates have a height of h and a width of t not shown in the figure). A dielectric slab with a thickness of d/3 is inserted in between the two parallel plates. The dielectric slab has a permittivity of...
8. (-/1.25 Points] DETAILS MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A student working in the physics laboratory connects a parallel-plate capacitor to a battery, so that the potential difference between the plates is 270 V. Assume a plate separation of d = 1.54 cm and a plate area of A = 25.0 cm. When the battery is removed, the capacitor is plunged into a container of distilled water. Assume distilled water is an insulator with a dielectric constant of...
2 R Additional Materials Reading 15. [-14 Points) DETAILS OSCOLPHYS2016 19.5.WA.045. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A large capacitance of 1.26 mF is needed for a certain application (a) Calculate the area the parallel plates of such a capacitor must have if they are separated by 4.77 um of Teflon, which has a dielectric constant of 2.1. m? (b) What is the maximum voltage that can be applied if the dielectric strength for Teflon is 60 x 10...
Please answer step-by-step. Thank you! Q4) (6 Points) A parallel-plate capacitor is constructed by filling the space between two square plates with blocks of four dielectric materials, as shown in the figure below. B) Find the equivalent capacitance, simplify the final expression. A/2 A) Plot the equivalent circuit. A/2 2d