A parallel-plate capacitor is constructed using a dielectric material whose dielectric constant is 2.10 and whose...
A parallel-plate capacitor is constructed using a dielectric material whose dielectric constant is 2.10 and whose dielectric strength is 2.20 108 V/m. The desired capacitance is 0.400 µF, and the capacitor must withstand a maximum potential difference of 4.00 kV. Find the minimum area of the capacitor plates.
Homework Answers
Concept - find the separation between the plates using the dielectric strength and the voltage between the plates. Use the equation for capacitance in terms of area, dielectric constant and separation to find the required value of area as shown below
-------------------------------------------------------------------------------------------------------------------
Let me know in the comment section, if something's
wrong
Add Answer to:
A parallel-plate capacitor is constructed using a dielectric
material whose dielectric constant is 2.10 and whose...
A parallel plate capacitor is constructed using a dielectric material with dielectric constant of 3 and...
A parallel plate capacitor is constructed using a dielectric material with dielectric constant of 3 and whose dielectric strength is 2x10^8 V/m. the desired capacitance is 0.250 mF, and the capacitors must withstand a maximum potential difference of 4 kV. Find the minimum area of the capacitor plates.
5. -/2 points SerCP11 16.A.P.063.MI. My Notes Ask Your Teacher A parallel-plate capacitor is constructed using...
5. -/2 points SerCP11 16.A.P.063.MI. My Notes Ask Your Teacher A parallel-plate capacitor is constructed using a dielectric material whose dielectric constant is 3.70 and whose dielectric strength is 3.00 x 108 V/m. The desired capacitance is 0.300 WF, and the capacitor must withstand a maximum potential difference of 4.00 kV. Find the minimum area of the capacitor plates. Om2
The dielectric to be used in a parallel-plate capacitor has a dielectric constant of 3.9 and...
The dielectric to be used in a parallel-plate capacitor has a dielectric constant of 3.9 and a dielectric strength of 1.9 × 107 V/m. The capacitor is to have a capacitance of 1 × 10-9 F and must be able to withstand a maximum potential difference of 5,500 V. What is the minimum area the plates of the capacitor may have? (Give your answer in scientific notation using m2 (meter square) as unit)
A certain substance has a dielectric constant of 2.8 and a dielectric strength of 18.0 MV/m....
A certain substance has a dielectric constant of 2.8 and a dielectric strength of 18.0 MV/m. If it is used as the dielectric material in a parallel-plate capacitor, what minimum area should the plates of the capacitor have to obtain a capacitance of 8.00×10-8 F and to ensure that the capacitor will be able to withstand a potential difference of 5.2 kV?
A certain substance has a dielectric constant of 2.8 and a dielectric strength of 18.0 MV/m....
A certain substance has a dielectric constant of 2.8 and a dielectric strength of 18.0 MV/m. If it is used as the dielectric material in a parallel-plate capacitor, what minimum area should the plates of the capacitor have to obtain a capacitance of 6.00×10-8 F and to ensure that the capacitor will be able to withstand a potential difference of 5.0 kV?
A certain substance has a dielectric constant of 3.9 and a dielectric strength of 22 MV/m....
A certain substance has a dielectric constant of 3.9 and a dielectric strength of 22 MV/m. If it is used as the dielectric material in a parallel-plate capacitor, what minimum area should the plates of the capacitor have to obtain a capacitance of 6.7 × 10-2 µ F and to ensure that the capacitor will be able to withstand a potential difference of 3.7 kV?
A certain substance has a dielectric constant of 2.4 and a dielectric strength of 21 MV/m....
A certain substance has a dielectric constant of 2.4 and a dielectric strength of 21 MV/m. If it is used as the dielectric material in a parallel-plate capacitor, what minimum area should the plates of the capacitor have to obtain a capacitance of 10 × 10-2 µ F and to ensure that the capacitor will be able to withstand a potential difference of 4.3 kV?
A certain substance has a dielectric constant of 3.2 and a dielectric strength of 15 MV/m....
A certain substance has a dielectric constant of 3.2 and a dielectric strength of 15 MV/m. If it is used as the dielectric material in a parallel-plate capacitor, what minimum area should the plates of the capacitor have to obtain a capacitance of 10 × 10-2 µ F and to ensure that the capacitor will be able to withstand a potential difference of 4.7 kV?
A parallel plate capacitor with an initial capacitance of 1200 µF has a dielectric with dielectric...
A parallel plate capacitor with an initial capacitance of 1200 µF has a dielectric with dielectric constant 2.20 inserted between its plates. The dielectric is also 1.50 times the width of the initial plate separation. What is the new capacitance after the dielectric has been inserted? A. 1760 µF B. 2640 µF C. 800 µF D. 818 µF E. 545 µF
dielectric constant of the paper is 3.5 The plates of a parallel plate capacitor are 4...
dielectric constant of the paper is 3.5
The plates of a parallel plate capacitor are 4 cm wide and 6 cm long. The plates are separated by a 1.8-mm-thick layer of paper (a) Calculate the capacitance of the device (in pF) using the dielectric constant of paper from this table. 0.0836 X pF (b) Any dielectric material other than a vacuum has a maximum electric field that can be generated in the dielectric material before it physically or chemically breaks...
5. -/2 points SerCP11 16.A.P.063.MI. My Notes Ask Your Teacher A parallel-plate capacitor is constructed using a dielectric material whose dielectric constant is 3.70 and whose dielectric strength is 3.00 x 108 V/m. The desired capacitance is 0.300 WF, and the capacitor must withstand a maximum potential difference of 4.00 kV. Find the minimum area of the capacitor plates. Om2
dielectric constant of the paper is 3.5
The plates of a parallel plate capacitor are 4 cm wide and 6 cm long. The plates are separated by a 1.8-mm-thick layer of paper (a) Calculate the capacitance of the device (in pF) using the dielectric constant of paper from this table. 0.0836 X pF (b) Any dielectric material other than a vacuum has a maximum electric field that can be generated in the dielectric material before it physically or chemically breaks...
Most questions answered within 3 hours.
-
Assume one of your finals has 50 questions on it, and
lucky for you, it's all...
asked 1 minute ago -
Rice Products in Bangladesh
Business behavior is derived in large part from the basic cultural
environment...
asked 1 hour ago -
The following base sequence is found for a mRNA fragment from
wild-type E. coli: 5'- UAUCAGUAGAUAAUGUAACC-3'...
asked 1 hour ago -
For this exercise, round all regression parameters to three
decimal places.
One of the two tables...
asked 2 hours ago -
What is the 5% level of significance for mean = 3.60, standard
deviation = 0.94, and...
asked 2 hours ago -
Prior to beginning work on this discussion, please read the
article by Hayley Peterson, 15 Companies...
asked 2 hours ago -
Which pair of aqueous solutions, when mixed, will form a
precipitate?
A) NaNO3 and AgC2H3O2
B)...
asked 2 hours ago -
1-Write an algorithm to get two numbers from the user (as
inputs) and calculate the sum...
asked 6 hours ago -
Define white-collar crime. What is the difference between
offender and offense-based definitions of white-collar crime? What...
asked 6 hours ago -
Consider a reaction which is 1st order with respect to A and 1st
order with respect...
asked 7 hours ago -
c++
The length of the hypotenuse of a right-angled triangle is the
square root of the...
asked 7 hours ago -
When a metal rod is heated, not only its resistance but also its
length and cross‐sectional...
asked 7 hours ago