A parallel-plate capacitor is constructed using a dielectric material whose dielectric constant is 2.10 and whose dielectric strength is 2.20 108 V/m. The desired capacitance is 0.400 µF, and the capacitor must withstand a maximum potential difference of 4.00 kV. Find the minimum area of the capacitor plates.
Concept - find the separation between the plates using the dielectric strength and the voltage between the plates. Use the equation for capacitance in terms of area, dielectric constant and separation to find the required value of area as shown below
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A parallel-plate capacitor is constructed using a dielectric material whose dielectric constant is 2.10 and whose...
A parallel plate capacitor is constructed using a dielectric material with dielectric constant of 3 and whose dielectric strength is 2x10^8 V/m. the desired capacitance is 0.250 mF, and the capacitors must withstand a maximum potential difference of 4 kV. Find the minimum area of the capacitor plates.
5. -/2 points SerCP11 16.A.P.063.MI. My Notes Ask Your Teacher A parallel-plate capacitor is constructed using a dielectric material whose dielectric constant is 3.70 and whose dielectric strength is 3.00 x 108 V/m. The desired capacitance is 0.300 WF, and the capacitor must withstand a maximum potential difference of 4.00 kV. Find the minimum area of the capacitor plates. Om2
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