Homework Answers
For mixture, Volume = V = 18.0 L
temperature = T = 0 oC = 273 K
Pressure = P = 1 atm
R = 0.082 L atm/mol K
Applyting formula,
PV= nRT
n = PV/RT = (1)(18.0)/(0.082*273) = 0.804 mol
n = total number of moles = 0.804
n = number of moles of (N2 + O2 + He)
0.804 = 0.250 + 0.250 + number of moles of He
number of moles of He = 0.804-0.500 = 0.304 mol
Molar mass of He = 4 g/mol
mass of He = molar mass*number of moles = 4*0.304 = 1.216 g = 1.22 g
mass of He present in mixture = 1.22 g
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