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Sa. sec(ax) •dx Va? - tan(ax) 5b. 35 (Ine)? dx 25 + (inverse trig functions) 7. The split method 6. Extended substitution 2x

10. (5 points) You want to maximize the area of an inscribed rectangle under the line Y(x) - 3x + 4 in the FIRST quadrant wit

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5.(a) da Pubstitute Seilan) vătan (2x) dz 21- is tan Case) = 2 -> a see (as) da=dz => See (ax) dx = dz Jazz ä Sin (2) + c sin(6) da 2 Sin 22 ſsin a-3 S sinx Sin & Cosa √ Sina-3 da ( (3+2)2.22 56323 32 +24) dz - 4{3 (2+dz + Sz dz} substitute, Sina- 3(7) da 2x+7 + 6x +10 2246 a+60+10 dat ( sa Gatio dat slechts to 17 la +6x+10) +62+10 = enla+ba+10l + tan (2+3) + (8) given, y

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