5) The molecular complex PbCl2- dissociates in water by the process PbCl²(aq) = Pb²+(aq) +4 CH...

Question

Question

5) The molecular complex PbCl2- dissociates in water by the process PbCl²(aq) = Pb²+(aq) +4 CH Kc = 4.1 x 10-16 The initial c

Answer 1

Answer #1

Answer : Concentration of Pb2+ ion achieved at equilibrium = 1.28 * 10^(-4) M

PbCl4 2- (aq) <==> Pb2+ (aq) + 4 Cl- (aq)

Kc for this equilibrium is given as

Kc = [Pb2+] [Cl-]^4 / [PbCl4 2-]

Step by step Solution is given in the image attached to calculate equilibrium concentration of Pb2+ ions.

Answer K= 4.1x10lb, initial concentration of Polly 0.0220M 9- Pollu (ap) That pet (aa) + 4 cu capi Initial concentration conc

Answer 2

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