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5) The molecular complex PbC142-dissociates in water by the process PbC142(aq) = Pb2+ (aq) + 4 CI Kc - 4.1 x 10-16 The initi
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5 + 40 at Pbci T p22 initially, after C e-x 48 At equilibrium So, Kc = Eb] [a] [Pb la x. (4839. c-x) Z e is less very as ke ior, Ke = 256 25 -16 exka 0.0222 4.1810 - x5 256 256 -20 3.52X 10 = x = 1.65x10 2+ is 4.65810u So the concentration of ph² ta

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5) The molecular complex PbC142-dissociates in water by the process PbC142"(aq) = Pb2+ (aq) + 4...
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