Data given :
Mass Of the fluid, m = 30.6 kg
Cube side length, a = 31 cm = 0.31 m
Solution :
Volume of cube , V = a^3 = 0.31^3 = 0.02979 m3
Weight of the fluid, F = mg = 30.6kg *(9.8 m/s2)= 299.88 N
Specific weight of the fluid : it is the weight of the fluid per unit volume.
Specific weight = weight of the fluid / volume
Hence specific weight of the given fluid = 299.88N/0.02979 m3 = 10066.44 N/m3 = 10.06 kN/m3
Approx answer is 10.1 kN/m3
Option a) 10.1 kN/m3
Question 25 unit conversions and formula sheet pdf A fuld has a mass of 30.6 kg...
FORMULA SHEET Question 16 A solid plastic cube with uniform density (side length 0.5 m) of mass 100 kg is placed in a vat of fluid whose specific gravity is 1.2. What fraction of the cube's volume floats above the surface of the fluid? O C. 2/3 O 1.45