Question

FORMULA SHEET Question 16 A solid plastic cube with uniform density (side length 0.5 m) of mass 100 kg is placed in a vat of fluid whose specific gravity is 1.2. What fraction of the cube's volume floats above the surface of the fluid? O C. 2/3 O 1.45

Answer 1

The object will float when the height of the object is equal to the weight of fluid displaced. let h is the dipped part of the object. Then 0.5 times 0.5 times h times 1.2 times rho_w = 100 rho_w = density of water rightarrow h = 100/0.5 times 0.5 times 1.2 times 1000 = 1/3 m so, the height above fluid = 1/2 - 1/3 = 1/6 m so, the fraction of object above fluid f f = 1/6 times 0.5 times 0.5/o.5 times 0.5 times 0.5 = 1/3 (option B)