Question

To calculate the torsional strain energy of the shaft with constant cross-section area below, we use the correct equation for every segment (0.5 m each) between the applied torques and sum up the result. The correct equation is: 900 N.m 200 N.m 0.5 m 300 N·m 0.5 m 0.5 m MPL 2EI M2 2GJ TML 2GJ οΣ TL 2GJ TL GJ т?м GJ

Answer 1

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of # To calculate the torsional strain energy the shaft use the correct segment each segment will for that is Strain energy E T²2 2GJ due to torque Hence, option 4th is correct Ang of To determine the sum of total strain energy the shaft is free body diagram of each section D Co.5 UOoNm B so Coo K 0.5 500nm Moon-m Potal strain energy = Il T2L гч 201J 2GJ .BC /CD ZGJ / AB 400²x0.5 300²x0.5t 500²x0.5t 1 265 Total strain - 250000 2GJ Energy Any