I. Make 21 random sample from a population with normal distribution (100,1)
H0 (mu=95)
Ha (mu>95)
II. Find the rejection region (alpha = 0.01)
III. Compute the test statistic.
IV. Tell me the appropriate conclusion for the test?
V. Tell me what condition is needed for the test results to be
valid? Is this condition satisfied? (alpha = 0.05)
I. Make 21 random sample from a population with normal distribution (100,1) H0 (mu=95) Ha (mu>95)...
. Suppose a random sample of 25 is taken from a population that follows a normal distribution with unknown mean and a known variance of 144. Provide the null and alternative hypotheses necessary to determine if there is evidence that the mean of the population is greater than 100. Using the sample mean, Y, as the test statistic and a rejection region > k}, find the value of k so that α = 0.15. of the form - Using the...
The five parts are: i. Null Hypothesis: H0 : µ =5.2 ii. Alternative Hypothesis: HA : µ < 5.2 iii. Rejection Region: Reject H0 if t statistic <−t49,.05 =−1.677 iv. Test Statistics: t = Y−µ0 S/pn = 5−5.2 0.7/p50 =−2.0203 <−t49,.05 =−1.677 v. Conclusion. Reject H0 at α = 5%. The data support that the mean dissolved oxygen count of the water is less than the reading at this location over the past year. What is the p-value?
1. In a test of H_0: mu = 100 against H_a: mu < > 100, the sample data yielded the test statistic z = -2.17. Find the p-value for the test. Here "<>" stands for "not equal". (a) 0.03 (b) 0.485 (c) 0.015 2. In a test of H_0: mu = 100 against H_a: mu < 100, the sample data yielded the test statistic z = -2.17. Find the p-value for the test. (a) 0.03 (b)0.485 (c)0.015 3. Specify the...
A random sample of n = 10 observations from a normal population produced x = 47.8 and s2 = 4.3. Test the hypothesis H0: μ = 48 against Ha: μ ≠ 48 at the 5% level of significance. State the test statistic. (Round your answer to three decimal places.) t = State the rejection region. (If the test is one-tailed, enter NONE for the unused region. Round your answers to three decimal places.) t > t <
A random sample of n = 1,000 observations from a binomial population contained 337 successes. You wish to show that p < 0.35. Given: H0: p = 0.35 versus Ha: p < 0.35 Solve: Calculate the appropriate test statistic. (Round your answer to two decimal places.) z =?? Provide an α = 0.05 rejection region. (Round your answer to two decimal places. If the test is one-tailed, enter NONE for the unused region.) z> ?? z<??
A random sample of size 16 from a normal distribution with mu=3 produced a sample mean of 4.5. a. Is the x distrobution normal? explain b. compute the sample test statistic z under the null hypothesis Ho: mu =6.3 c. For H1: mu <6.3, estimate the P-value of the test statistic d. For a level of significance of 0.01 and the hypothesis of parts (b) and (c), do you reject or fail to reject the null hypothesis? explain.
Test using the p-value approach with ? = 0.05.State the null and alternative hypothesis.H0: ? < 98.6 versus Ha: ? > 98.6H0: ? = 98.6 versus Ha: ? > 98.6 H0: ? = 98.6 versus Ha: ? < 98.6H0: ? = 98.6 versus Ha: ? ≠ 98.6H0: ? ≠ 98.6 versus Ha: ? = 98.6Find the test statistic and the p-value. (Round your test statistic to two decimal places and your p-value to four decimal places.)z=p-value=State your conclusion.The p-value is greater than alpha so H0 is not rejected. There is insufficient evidence to indicate that the average body temperature for healthy humans deviates from 98.6°.The p-value is less than alpha so H0 is rejected. There is sufficient evidence to...
You are testing H0: μ = 100 against Ha: μ < 100 based on an SRS of 21 observations from a Normal population. The data give x̄ = 9.1 and s = 3.6. The value of the t statistic (±0.01) is _______
Consider the following hypothesis test. H0: μ ≤ 50 Ha: μ > 50 A sample of 60 is used and the population standard deviation is 8. Use the critical value approach to state your conclusion for each of the following sample results. Use α = 0.05. (Round your answers to two decimal places.) (a)x = 52.5 Find the value of the test statistic. State the critical values for the rejection rule. (If the test is one-tailed, enter NONE for the...
(a)Test using the p-value approach with ? = 0.05.State the null and alternative hypothesis.H0: ? < 98.6 versus Ha: ? > 98.6H0: ? = 98.6 versus Ha: ? > 98.6 H0: ? = 98.6 versus Ha: ? < 98.6H0: ? = 98.6 versus Ha: ? ≠ 98.6H0: ? ≠ 98.6 versus Ha: ? = 98.6Find the test statistic and the p-value. (Round your test statistic to two decimal places and your p-value to four decimal places.)z=p-value=State your conclusion.The p-value is greater than alpha so H0 is not rejected. There is insufficient evidence to indicate that the average body temperature for healthy humans deviates from 98.6°.The p-value is less than alpha so H0 is rejected. There is sufficient evidence to...