A random sample of n = 10 observations from a normal population produced x = 47.8 and s2 = 4.3. Test the hypothesis H0: μ = 48 against Ha: μ ≠ 48 at the 5% level of significance.
State the test statistic. (Round your answer to three decimal places.) t =
State the rejection region. (If the test is one-tailed, enter NONE for the unused region. Round your answers to three decimal places.)
t >
t <
Test statistic = t
= ( - ) / s / n
= (47.8 - 48) / sqrt 4.3 / 10
t = -0.305
Test statistic = -0.305
n = 10
df = 9
t > 2.262
t <-2.262
A random sample of n = 10 observations from a normal population produced x = 47.8...
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