n Express the limit lim (2 cos(272) +6) Ax; over [4, 8] as an integral. n...
n Express the limit lim (3 cos” (272,-) + 8)Ac; over (2,6) as an integral. 12 00 i=1 Provide a, b and f(x) in the expression [ f(e)dr. a = b f()
(1 point) The limit lim /2x + (x)?Ax 11 can be expressed as a definite integral on the interval [1, 8] of the form $(x) dx Determine a, b, and f(x). a = b= f(x) =
thankYou Express the limit as a definite integral n lim Σ ( sec c?q)4 Axk, where P is a partition of [-67, 6x] ||P|| → 0k=1 6 on secx 12x dx 6 1 ов. | | sec x ds oci tan x dx 6 6 00 1 sec ? x dx 6 Use the graph to evaluate the limit. OA. 2 lim f(x) OB. 0 X0 C. - 2 Ay O D. The limit does not exist. 5 4 3...
Express the limit as a definite integral. n lim Σ 1P10k1 TCK' AXk, where P is a partition of [6, 12] 6 OA. 7x6 dx 12 n B. 7x dx 1 12 Oc. zxdx de 12 OD | 42x2 dx Find the derivative. to y = = S cos Vt dt 0 O A. cos (x3) O B. sin (x3) OC. 6x5 OD. cos (x3) - 1 cos (x3) Solve the initial value problem. dy = x(2+x2)), y(0) = 0...
Express the limit as a definite integral on the given interval. lim n00 1 = 1 X; In(1 + x2) Ax, [2, 4] SI dx
8. Express the limit as a definite integral on the given iterval. lim :0;)2 + 44.2 on (1.3) (a) Si 7244dx (b) S dx (e) tada (d) $3 2274 d.
Given in n express the limit as n → as 3 [4+6-15) - (6+65) "sludz. a definite integral, that is provide a, b and f(x) in the expression a .b
A. Express the limit as a definite integral on the given interval. B. Use the form of the definition of the integral to evaluate the integral. n Š lim n-> Xi Ax, [1, 3] (xi +13 * 2 i=1 3 6 (2x - x2) dx
5. (-/1 Points] DETAILS SCALC8 4.2.503.XP. Express the limit as a definite integral on the given interval. n lim 3x;* + (x;*)2 Ax, [1,4] i = 1 dx
Question 4 4.1 Express the limit as a definite integral on the given integral: 1-x} Ax , [2,6] lim Σ=1 a. (2 Marks) n->00 4+x} lim (?-1 - Ax ,[1,3] (xi) - 4 b. (2 Marks) n->00 4.2 Evaluate the following expressions. Show your calculations. $=1(2p – p2) b. En-o sin a. (2 Marks) пп (2 Marks) 2 C. 2m +2 53 Lm=1 3 (2 Marks) [Sub Total 10 Marks]