Question

1) The molarity of naphthaline in a solution of naphthalene (C10H8, MW = 128.8), a non-ionizing and nonvolatile solute, and benzene (CH, MW = 78.11), a volatile solvent, is (C10Hg] =0.086 M. The density of the solution is D = 0.8748 g/cm. Find the following: a) The osmotic pressure exerted by the solution, at T = 25.0 °C. Give your final answer in units of torr. [8 points) b) Xn, the mole fraction of naphthalene in the solution. [15 points]

Answer 1

0 osmotic pressure T=CRT + (0-086 .) *(0.032) Latin 2004 atm | atm = 760 torer T= 1599.04 tors 2 Mole fraction of napthlene = Nog moles y napthlene Total No. of moles No. of moles of mapthlene = Given Mass mol, Mass - Given Mass molauity Mol, Mass vol. og sol, in L 0,086 = Given mass 188.8 & Given mass = 11.07 g moles y Naptheme = 11:078 128.8 g/mol -0.085 mol No. of moles Benzene Given mass mol mass o S=0.8740 g M > M=874,8 1000 ml moles Benzene 874,8 Jl-l9gmo 78.11 Mole fraction of Napthlene = 0,085 11. 19+0.085 2 0.00753 g 8=M <3 mi M-874.89 o. No g g