Question

Part 3. Problems 1) The molarity of naphthaline in a solution of naphthalene (CHs, MW - 128.8), a non-ionizing and nonvolatile solute, and benzene (CH, MW = 78.11), a volatile solvent, is [CH] -0.103 M. The density of the solution is D = 0.8759 g/cm?. Find the following: a) The osmotic pressure exerted by the solution, at T - 25.0 °C. Give your final answer in units of torr. [8 points) b) Xn, the mole fraction of naphthalene in the solution. [15 points) ROGUE NEW FOR

Answer 1

exerted by Ans @The osmotic press wie solt is given as P= iMRI Now, as hapth alene is non-valetile i= l M= a.la3m R= 0.0821. Lath moll K- T=25°C = 298k So, B Osmotic pressure is P= 1,0.103xo.082) × 298 S 2.52 atm 2.52X 760 torr 191518 tarr (b) Mole fraction of salute: Let take IL selh IL soll. Then, moles of napthalene present in it isis a los moles Males Now, Mass of 6.8759 g/cm? Xlooo cm3 of hap that ene الحلال S 815.9 grams

of - So. Mass water present in it = 875.9 - Aula3x128e8g 8.62.63359 ł 862 So, Moles of water in soln 862.634 moles 47.824 males Thus, the mole mole fraction solute of colo3 cool03 +4 1.924) 20145 x 10-3