What is the period of the motion
x ( t ) = 5 sin ( 2 π t ) ?
What is the frequency of the motion x ( t ) = 5 sin ( 2 π t ) ?
1.What is the period of the motion What is the period of the motion x ( t ) = 5 sin ( 2 π t ) ? a.0.5 s. b.2 s. c.5 s. d.none of the other answers. e.1 s.
Question 13 1 pts What is the period of the motion *(t) = 5 sin(2nt)? If you need them I = md, Iring = MR Icylinder = { MR? Isphere = MR t=la, F=ma, T = Fr sin T= AL F= Ap F = -ka s=Or, v=wr, p = mv, L = IW Δω Δυ a = AT ΔΘ Q= 4) At ) a = A) At W = Fs cose, U = mgh, K = į mv?, U =...
The function x = (4.3 m) cos[(3πrad/s)t + π/5 rad] gives the simple harmonic motion of a body. At t = 2.2 s, what are the (a) displacement, (b) velocity, (c) acceleration, and (d) phase of the motion? Also, what are the (e) frequency and (f) period of the motion?
A particle executes harmonic motion described by x= 2.5 sin (3.5πT). Where x is in meters and t is in seconds. A) at t=3s what is the acceleration B)What is the period T
) + 4 sin(300m), w a) (2 points) Given the signal x(t) = 5 cos(200 period, T, is needed to avoid aliasing? 3. b) (8 points) If you sample x() with sampling period T/2 where T is your answer to part a), what is the resulting discrete signal, x[n]?
x(t)=0.22m cos (89.5 rad/s)t what is the period of the motion in s?
No. 4 (5 points) Given a signal x(t)= 1 + sin(2t). (1) Is it a period signal or not? If so, write -down period T (2) Calculate its size (signal energy? or signal power?)
The function x = (2.5 m) cos[(5π rad/s)t + π/5 rad] gives the simple harmonic motion of a body. Find the following values at t = 7.0 s. (a) the displacement m (b) the velocity (Include the sign of the value in your answer.) m/s (c) the acceleration (Include the sign of the value in your answer.) m/s2 (d) the phase of the motion rad (e) the frequency of the motion Hz (f) the period of the motion s
For 0 x π , 0S9, π , and 120 , solve the 2-D wave equation subject to the following conditions. u(0,y,t)-0, u(T.yt):0, u(x,0,) u(x,π, t) 0, 0 Boundary condition: C11 1 u(x),0)-sin(x)sin(2y) + sin(2x)sin(4y), 0 at It=0 Initial condition:
For 0 x π , 0S9, π , and 120 , solve the 2-D wave equation subject to the following conditions. u(0,y,t)-0, u(T.yt):0, u(x,0,) u(x,π, t) 0, 0 Boundary condition: C11 1 u(x),0)-sin(x)sin(2y) + sin(2x)sin(4y), 0 at It=0 Initial condition: