Question

Question 13 1 pts What is the period of the motion *(t) = 5 sin(2nt)? If you need them I = md, Iring = MR Icylinder = { MR? Isphere = MR t=la, F=ma, T = Fr sin T= AL F= Ap F = -ka s=Or, v=wr, p = mv, L = IW Δω Δυ a = AT ΔΘ Q= 4) At ) a = A) At W = Fs cose, U = mgh, K = į mv?, U = 1 km2 w= 27 f, f= k = ** O1s. O2 s. O 5s. none of the other answers. O 0.5 s.

Answer 1

we have the waveform

$x(t)=5sin(2\pi t)$

Comparing this with the standard sinusoidal waveform i.e.

(t) = Asin (wt)

We get the amplitude of wave as 5, and the angular velocity ω =2π

Also, we know,

$\omega = 2 \pi f = \frac{2 \pi}{T}$                where f is the frequency and T the time period .

So, for ω =2π, we get the time period T=1s.

So, option 1 is correct.