Question

Please use the equation on the sheet below the question

ONLY do box 2b-box 4. & the question

Trial Mass Amplitude Spring k (N/m) box 1 Ang Freq (o measured) Error Ang Freq (rad/s) (o expected) (grams) 250 (cm) (%) 1 5 box 2b box 2a 9.01 250 7.5 same as trial 1 box 3 XXXXXX XXXXXX 3 500 same as trial 1 2 x spring #1 Table 1: Simple Harmonic Motion lab data for springs 5 box 4 XXXXXX XXxxxx 4 500 6 XXXXXXXXX 9.01 XXXXXX 6.(35) Answer the questions and fill in the boxes of the table as requested. Box 1: You hang the 250g mass on the spring and it stretches 13cm. What is k? me0.25 kg J KR=ms K19-23 Box 2a: Calculate the expected omega (o). Box 2b: Compare to measured o and find error. TA O.25 3.8 What is the likely source of that error? What are you "testing for" in trial 2? What variables are being "controlled"? Box 3: What omega (o) do you "expect" to get in trial 2? What are you "testing" for in trial 3? Box 4: What omega (o) do you "expect" to get in trial 3? Does the measured omega in trial 4 make sense? Why or why not?

Answer 1

Box 1:

The spring force will be equal to the force of gravity:

Kx = mg

K = mg/x

K = (250 x 10^-3 x 9.81) ÷ (13 x 10^-3)

k = 18.86 N/m

Box 2a:

We know that,

Box 1: The spring force will be equal to the force of gravity: Kx = mg K = mg/x K = (250 x 10-3�x 9.81) � (13 x 10-3) k = 18.86 N/m Box 2a: We know that, w = root k/m w = root 18.86 / 250 times 10^- 3 kg Here, w = 8.68 �rad/s Box 2b: The percentage Error can be calculated by the below formula Percentage - Error = Vertical-bar E.V - M.V/E.V Vertical-bar times 100 Percentage - Error = Vertical-bar 8.68 - 9.01/8.68 Vertical-bar times 100 % Error = 3.8 % Box 3: Again, using the same value of K for mass 250g, w = 8.68�rad/s Box 4: Here K = 18.86 N/m and m = 500g = 500 x 10-3�kg Hence, w = root 18.86/500 times 10^- 3 kg w = 6.14 rad/s

Here,

rad/s

Box 2b:

The percentage Error can be calculated by the below formula

% Error = 3.8 %

Box 3:

Again, using the same value of K for mass 250g,

rad/s

Box 4:

Here K = 18.86 N/m and m = 500g = 500 x 10^-3 kg

Hence,