Question

UESTION 4 16 po (Virtual Work Truss) Problem 4. Virtual Work Method. Determine the horizontal deflection at B. Assume all members are pin- connected at their ends. AE is constant (46 points) 3 kip Seh 4 ft 3 ft B 4 ft. 6 ft А E What is the horizontal displacement at B TTT Arial 3 (12pt) vт !!! III Words:0 Path:p 16 points QUESTION 5 (Virtual Work Determinate) Problem 5. Virtual Work Method. Determine the horizontal displacement at B. The support at A is a pin and D is a roller. El is constant (16 points) 4 kipit бен B 15 ft С D

Answer 1

- 0 x Truss Analysis Module Back File Stresses Help New Truss Member Forces Reactions 0. 3 6. Back C Create Erase 8. C Members Supports Loads Compute 53.1300 1.0 4. Using the left mouse button, click at the desired joint and drag in the direction of the load to be removed. 53.1300 53.130 0. Type here to search O TT ? A » ENG 08:20 PM 30-07-2020

method of virtual work : Deflection A= Σ PEL AE Where p= force in members due to external force K= force in members due to it load L = A= area Es modulus of Masticity Calculating P → FED S8536-87° 0= tau! 2 0 = 36.87 length P =0.6FCD 3k Pored I= tension equilibrium E Fx=0 FBC V FCD 20536187°=0.8FCD C = Comprension equations 3-0.6FCD = 0 FLD = 5K

Efy=0 FBL -01845=0 FBC = 4k © at B 4K FBD = 0 > FBD FAB FAB = 4K © at D (Fcd=5k FOE = 5k FAD=0 FAD FDE at A luk FAE FAE=0 TAY Calculating K applying wit load at i at hoc Nofio FBC=0 FED=0 FBC at B FB (=0 Ik FBD FAB FBp=, ko FBC= FAB=0 Ik May >EX ТЕу

FAE = 0183 sin36,870 EMACO 6X Ey +1X4=0 Ey = -7/ k v Ex=IK Efx=0 {fyzo Ay= 2 k 2 at A LOFAD > FAE FAD S 36.896 = FAD = 0.83 k© FAE = 0.5k 0 at D 1k obrane 0183K "FDE 0.83 C050 -FDE C050=0 FDE = 0.83 K60 P K PKL 0 0 -4 -4 lft 4 4 5 5 Member AB BC CD DE EA BD AD 2ooo o 0 0.83 015 5 0 0 20175 6 3 5 0 o -0.83 E 20175 SB= 20125 AE (left)