Question

Path: Words:0 QUESTION 6 16 points (Virtual Work Indeterminate) Problem 6. Virtual Work Method. Determine the reaction at A. The support at A is a roller and C is fixed. El is constant. (16 points) RA 10 ft 5 ft 4 kip B What is the reaction at A TTT Arial 3 (12pt) T !!! Path:p Words. QUESTION 7 22 points Sav (Slope-Deflection) Problem 7 Using Slope-Deflection Method, write all equations using numeric standard decimal values for calculations (Not Eractions. when known or able to be calculated, necessary to solve for the MOMENTS and SLOPES in each span. The support at "A" SETTLES DOWNWARD 0.2. El is constant Assume support at "A" is fixed, support "C" is found and "B" is a roder. DO NOT SOLVE for the internal moments. 22 point

Answer 1

C 1441 15 ft B k 4 kip 10 ft RA The given loading can be written + DAI I 4 kip and RA DAI + DAZ = 0 displacement due to 4 kip load at A displacement due to redundant RA at A DAZ Moments (Real) due to real load (4 kip AB (OSNS 10H) ! IM M=0 kip-ft A x BC (OSK354) 19 = 41 kip-ft LI -Akip B

Virtual moments due to virtual unit load (ikip) at A I kép acting in the direction of redundant RA AB FOLRE lo ft) m = -x kip-ft 2 키 7:59 Ikip BC COST < 5 ft) me - 10 kip-ft 10 ft B I kip 3 EI Member 2 EI O AB oto 10 EI 4K - 10 o to 5 Вс AAI + AAR =0 AAI + RA. AU Au → displacement at A due to virtual unit load By principle of virtual work AAL Mm du SES EI mm da AU EI

Sam da + RA Smi m² du EI m² dx Mm dat mm dx + RA m² da EI + - 0 het EI EI AB Be AB Be - 400 - + OVO + S 10p x² da EI du f RA • da EI EI 0 E I i constant 10 5 +10041 =0 o -2011| + Ral -20 x25 + R ( 500) 3 RA = 0.6 kip (acting downwards)

14 kip-ft 4 kip 0.6 kip 2 0.6 kip