molar mass of compound = 869.1 gm/mol
molar mass of imperical form (CH2Br2) = 173.8 gm/ mol
(molar mass of impirical formula)n= molar mass of compound.
(CH2Br2)n= 869.1
(173.8)n = 869.1
n= 869.1 / 173.8
n= 5 so by putting the value of n in (CH2Br2)n we get
(CH2Br2)5
C5H10Br10 is the ans where
C= 5 , H= 10 , Br = 10
» A Click Submit to complete this assessment. Question 4 the empirical formula of a compound...
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