Question

A 77.18 g sample of a hydrocarbon (CxHy) has a mass of carbon that is equal to 66.89 g


A 77.18 g sample of a hydrocarbon (CxHy) has a mass of carbon that is equal to 66.89 g. Given this information, determine the empirical formula of this hydrocarbon. MMC = 12.01 and MMH = 1.008) 

Throughout your calculations, maintain at least 4 significant figures. 


In each answer box place the appropriate subscript for each spoiled element which in essence conveys this compound's empirical formula. 

3 0
Add a comment Improve this question Transcribed image text
Answer #1

Mass of carbon =66.89 g

Mass of Hydrogen = 77.18-66.89 =10.29 g

Moles of carbon, x=66.89/12.01 = 5.569

Moles of Hydrogen, y=10.29/1.008 = 10.21

C5.569 H10.21

Empirical formula is C1H1.833

C 1 H 1.833

Add a comment
Know the answer?
Add Answer to:
A 77.18 g sample of a hydrocarbon (CxHy) has a mass of carbon that is equal to 66.89 g
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A 0.271-g sample of a gaseous hydrocarbon (CxHy) occupies 226 mL at 22.0 ºC at 735...

    A 0.271-g sample of a gaseous hydrocarbon (CxHy) occupies 226 mL at 22.0 ºC at 735 torr. Calculate the molar mass of this hydrocarbon in g/mol. Express your answer as a number (not scientific notation) without units; for full credit, the last digit of your answer should be within ±1 of the correct value, with an appropriate number of significant figures. Molar mass: Answer          g/mol. Complete combustion of 1.532 g of this gaseous hydrocarbon (CxHy) yields 4.484 g of carbon...

  • Gaseous hydrocarbon A 0.271-9 sample of a gaseous hydrocarbon (CxHy) occupies 117 mL at 22.0°C at...

    Gaseous hydrocarbon A 0.271-9 sample of a gaseous hydrocarbon (CxHy) occupies 117 mL at 22.0°C at 735 torr. Calculate the molar mass of this hydrocarbon in g/mol. Express your answer as a number (not scientific notation) without units, for full credit, the last digit of your answer should be within 11 of the correct value, with an appropriate number of significant figures. Molar mass: g/mol. Complete combustion of 1.532 g of this gaseous hydrocarbon (CxHy) yields 4.640 g of carbon...

  • » A Click Submit to complete this assessment. Question 4 the empirical formula of a compound...

    » A Click Submit to complete this assessment. Question 4 the empirical formula of a compound is CH2Bre, what is its molecular formula given that it has a molar mass of 889.1 g/mol. In each answer box place the appropriate subscript for each specified element which in essence conveys this compound's molecular formula. С H Br Click Submit to complete this assessment.

  • 16. A 2.288 g sample of a hydrocarbon consisting of only carbon and hydrogen(NO oxygen burned...

    16. A 2.288 g sample of a hydrocarbon consisting of only carbon and hydrogen(NO oxygen burned in an excess of oxygen gas (O2), producing 6.277 g CO2 and 5.139 g H20. What is the empirical formula of the hydrocarbon? (5 points) (FW CO2 = 44.01; H2O = 18.02; H = 1.01; C =12.01: 0 = 16.00; O2 = 32.00)

  • 6.0 grams hydrocarbon sample were made to react with oxygen gas to produce 17.6 grams of...

    6.0 grams hydrocarbon sample were made to react with oxygen gas to produce 17.6 grams of carbon dioxide according to the equation: CxHy(g) + O2(g) ---------- CO2(g) + H20(l) where x = subscript for C, y = subscript for H a. How many grams of C are there in 17.6 grams of CO2? b. How many grams of C are there in the hydrocarbon sample? c. How many moles of C are there in the hydrocarbon sample? d. How many...

  • 2) A 1.000 g sample of a hydrocarbon (which is a compound that contains only carbon...

    2) A 1.000 g sample of a hydrocarbon (which is a compound that contains only carbon and hydrogen) was burned in oxygen, and the carbon dioxide and water produced were carefully collected and weighed. The mass of the carbon dioxide was 3.385 g, and the mass of the water was 0.692 g. What was the empirical formula of the hydrocarbon? A. C5H12 B. CsH6 C. CįH6 D. C H2 E. CįH star 1.00

  • A compound contains only carbon, hydrogen, and oxygen. Combustion of 18.92 g of the compound yields 27.73 g of CO2 and...

    A compound contains only carbon, hydrogen, and oxygen. Combustion of 18.92 g of the compound yields 27.73 g of CO2 and 11.35 g of H2O. The molar mass of the compound is 90.078 g/mol. *Each part of this problem should be submitted separately to avoid losing your work* 1. Calculate the grams of carbon (C) in 18.92 g of the compound: grams 2. Calculate the grams of hydrogen (H) in 18.92 g of the compound. grams 3. Calculate the grams...

  • Naphthalene, a hydrocarbon, has an approximate molar mass of 128 g/mole. If the combustion of 64...

    Naphthalene, a hydrocarbon, has an approximate molar mass of 128 g/mole. If the combustion of 64 produces 0.3599 g H20 and 2.1977 g CO2, what is the molecular formula of this compound? 3. A mass of 0.4113 g of an unknown acid, HA, is titrated with NaOH. If the acid reacts with 28.10 mL of 0.1055 M NaOH(aq), what is the molar mass of the acid? 4. The amount of calcium in a 15.0-g sample was determined by converting the...

  • 1.Our hydrocarbon has the molecule or formula C6H12 which of the following statements interpret this information...

    1.Our hydrocarbon has the molecule or formula C6H12 which of the following statements interpret this information correctly A. 6 g of C combines with 12 grams of H to form this compound B. One mol of this compound contains 6 mol of C and 12 mol of H C. The ratio of C:H in this compound is 1:2 2.Quinine, which was 1st isolated in 1820 from the bark of a Cinchona tree, has been used for hundreds of years to...

  • Zinc forms the cation, Zn2+. A mystery anion X is represented as X2. Given this information,...

    Zinc forms the cation, Zn2+. A mystery anion X is represented as X2. Given this information, what is the molecular formula of the salt it forms with zinc? (Chemical formula use subscript numbers, but for this question any required numbers may be formatted normally. Also, do not insert any spaces between the elements.) Answer: Library Home Students According to the VSEPR electron pairs in the valence energy level repel each other and are therefore arranged as far apart as possible....

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT