Question

A compound contains only carbon, hydrogen, and oxygen. Combustion of 18.92 g of the compound yields 27.73 g of CO2 and 11.35 g of H2O. The molar mass of the compound is 90.078 g/mol. *Each part of this problem should be submitted separately to avoid losing your work*

1. Calculate the grams of carbon (C) in 18.92 g of the compound: grams

2. Calculate the grams of hydrogen (H) in 18.92 g of the compound. grams

3. Calculate the grams of oxygen (O) in 18.92 g of the compound. grams

Based on your previous answers, calculate

1. the moles of carbon (C) in 18.92 g of the compound:  moles
2. the moles of hydrogen (H) in 18.92 g of the compound:  moles
3. the moles of oxygen (O) in 18.92 g of the compound:  moles

Divide each mole quantity that you determined in the previous question by the smallest number of moles to determine the correct empirical formula.

Enter the correct subscript for each atom using the smallest whole number.
Enter a 1 if that is the smallest whole number, don't leave the box empty. C  H  O  

Now determine the molecular formula. Remember that the molar mass of the compound is 90.078 g/mol.

Enter the correct subscript for each atom using the smallest whole number.
Enter a 1 if that is the smallest whole number, don't leave the box empty.

C  H  O  

Answer 1

18-92, %및 Caubon in Ooganic Compound= l2.xm】지00 18:92 39 .91 % = ax 11-35x100 = 6。6イヅ。 18 × 18.92 100-39.91-6.67 53-36%

loo T56 Н.in 18.929-6。61 × 18-9 2 loo 3tonall40İn-18.929-. 53:36 1842 1 2. 12 %. 63-2 0-63/o 63)

EmpuuitaL cou mass moleaulao mula C3H6O3 21603