Question

Find the particular solution of differential equation -t du 2e dt at, initial condition, a 2(0)=1.

Answer 1

find the particulare Solution of differential Cliation xét da with initial at da at condition: x()=1 > x et dix at dt redra it idt ét x dx = t. et dt Sider we get Integrating both Tx dx = Stet.dt t. Jetat flatt. fet dit ) et → 223 2 » x² t.et - Jet, at 2

→ x² = t.et – et to 2 (1) where a is Integration constant using initial condition, XO (13 0.ecco + c S 2 → o-ite c=3 22 / 2 how equation 6 becomes 2 t. et Let + 3 2 1 lt 2 2 - (1-1) + 3 2 et Answer