Question

CAN SOMEONE CALCULATE THIS FOR ME FOR MY FIVE TRIALS AND SHOW MY HOW YOU DID IT??

(15) Calculate the number of elementary charges that are on each tape using the total charge on each tape that you calculated in the previous step and the elementary charge, qe = 1.602 x 10-1°C. (16) Calculate an estimate of the number of atoms at the surface of the tape. Assume that the atoms are arranged in a square lattice, as shown in Figure 7-2, where the length of one side is S = (0.40 + 0.04) nm (or 10%). # of atoms = Total Area Area per atom 82 Figure 7-2. Atomic unit cell of the surface of a piece of tape. (17)Determine how many surface atoms are there for each charged atom using: unbalanced charges per atom = # of elementary charges # of atoms

Answer 1

Table 3 gives information about the net charge that is present in the tape.

We have to divide it by the elementary charge = 1.6*10^-19 C (charge of an electron) to get the number of charges.

From the figure 7.2, we can see that a square of area S*S consist of 4*1/4 = 1 atom.

So, total area /area per atom will give the no of atoms.

The table is given below.

Q	L	B	Trial no	# of elementary charges	# of atoms	Charge per atom
3.7583E-07	0.115	0.03	1	2.34894E+12	2.15625E+16	0.000109
3.445E-07	0.103	0.0275	2	2.15313E+12	1.77031E+16	0.000122
2.3804E-07	0.093	0.019	3	1.48775E+12	1.10438E+16	0.000135
2.1301E-07	0.085	0.017	4	1.33131E+12	9.03125E+15	0.000147
1.8168E-07	0.055	0.0145	5	1.1355E+12	4.98438E+15	0.000228