Question

A train is moving pass a crossing where cars are waiting for it to pass. While waiting, the driver of the lead car becomes sleepy and rests his head on the steering wheel, unintentionally activating the car's horn. A passenger in the back of the train hears the horn's sound at a frequency of 444 Hz and a passenger in the front hears it at 415 Hz. Find the train's speed and the horn's frequency, assuming the sound travels along the tracks. Take the speed of sound to be 343 m/s

a) The trains speed (in m/s).

b) The horn's frequency (in Hz).

Answer 1

fost Given data the The frequency of honom heard by passengen in the back of the train is- for 444 Hz The frequency of horrom heard by the passenger in the front of train is- Se 4152414 415 HE the expression to calculate the frequency in front of the train is as followst Sf f = Sowjee frequen ey (horn frequr ou fse do eneye fus-speed of sound = 343 ms Nge speed of train The expression to cal qwerte the freq ey Im back of the train is as follows fb e fs l NS ENA! on, fss frontal companing equation @ and ② FP CW-v1) "(*) US-VI VS ws usoni wen NS VSANI ffɛ 415 Hz, fo=440Hz Vis 343 mg 343 343 Ć 9154 Z4440 343-N1 343+NA to of A 343 1343 ory (343.-Ny 343+NA ON, 3434Ny E (343~ND) x groz dny 343 +NY 2 367001 - 8007ng ov, 21067 Ny 36.708) - 343 on 2007 N1 2 24.01 11.599 m's 1:14:599.nys Thus speed of the train : The frequency of the horrom calcuated as fee for US-VI ཅ) དཔ ་ ： ༠ be combe 7 343 9154 843 - 1599 e 429.52 Ha 429.52 Ha Thus frequency of horom Scanned with CamScanner