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If chemical reaction (1) has a AH of 68 kJ associated with it, what is the AH of reaction (2)? (1) N2(g) + 202(g) -> 2NO2(g)
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Answer #1

The multiplication factor for the reaction second is = 3
It means moles of rectants in reaction second is three times than that of reaction 1.

Hence, \Delta H must be multiply by 3.

\Delta H = 68 X 3 = 204 kJ

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