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For the reaction 2NO(g) + O2(g) —>2NO2(g) AH° = -114.2 kJ and AS° = -146.5 J/K...
2NO(g)02(g)2NO2(g) AH° =-114.2 kJ and AS° =-146.5 J/K The equilibrium constant for this reaction at 321.0 K is Assume that AH° and AS° are independent of temperature
2- For the reaction 2NO(g) + O2(g)2NO2(g) H° = -114.2 kJ and S° = -146.5 J/K The equilibrium constant for this reaction at 289.0 K is ---------- . Assume that H° and S° are independent of temperature.
pt Use the References to access important values if needed for pt For the reaction pt 2NO(g) + O2(g)—>2NO2(g) pt AH° = -114.2 kJ and AS = -146.5 J/K pt The equilibrium constant for this reaction at 256.0 K is pt Assume that AHⓇ and AS are independent of temperature. pt pt Submit Answer Try Another Version 3 item attempts remaining pt pt pt - pt pr
For the reaction N2(g) + O2(g)2NO(g) AH° - 180.6 kJ and AS - 24.9 J/K The equilibrium constant for this reaction at 301.0K is Assume that A Hº and AS are independent of temperature. Submit Answer Retry Entire Group 8 more group attempts remaining
Given the standard enthalpy changes for the following two reactions: (1) N2(g) + O2(g) +2NO(g) AH° = 181.8 kJ (2) N2(g) + 202(g)—>2NO2(g) AH° = 66.4 kJ what is the standard enthalpy change for the reaction: (3) 2NO(g) + O2(g) 2NO2(g) AH° = ? Submit Answer Try Another Version 2 item attempts remaining
4. For the reaction Ny() + O2()—>2NO(g) AH-181 kJ and AS - 24.9 J/K AGⓇ would be negative at temperatures (above, below) Enter above or below in the first box and enter the temperature in the second box. Assume that AHⓇ and AS are constant. K Submit Answer Retry Entire Group 9 more group attempts remaining For the reaction CaCO3(s) CaO(s) + CO2(g) AH° -178 kJ and AS - 161 J/K AGⓇ would be negative at temperatures (above, below) K...
For the reaction N2(g) + O2(g)->2NO(g) AH° = 180.6 kJ and AS = 24.9 J/K The equilibrium constant for this reaction at 267.0 K is Assume that AHⓇ and ASº are independent of temperature.
Consider the reaction 2CO2(g) + 5H2(g)- *C2H2(g) + 4H2O(g) for which AH° = 46.50 kJ and AS° = -124.8 J/K at 298.15 K. (1) Calculate the entropy change of the UNIVERSE when 1.958 moles of CO2(g) react under standard conditions at 298.15 K. J/K A Suniverse (2) Is this reaction reactant or product favored under standard conditions? (3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction...
For the reaction S(s,rhombic) + 2CO(g) SO2(g) + 2C(s,graphite) AH = -75.8 kJ and AS =-167.6J/K The standard free energy change for the reaction of 1.88 moles of S(s,rhombic) at 294 K, 1 atm would be This reaction is (reactant, product) favored under standard conditions at 294 K. Assume that AH° and AS are independent of temperature. Submit Answer Try Another Version 2 Item attempts remaining
For the reaction 2802(g) + O2(g)—>2503(g) AH° = -197.8 kJ and AS° = -187.9 J/K The equilibrium constant for this reaction at 298.0 K is Assume that AHⓇ and AS™ are independent of temperature.