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For the reaction 2802(g) + O2(g)—>2503(g) AH° = -197.8 kJ and AS° = -187.9 J/K The equilibrium constant for this reaction at
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! Answered ;- given data AHO = -197.8KJ OSO = -187.9 Jlk T= 298.0 K given the reaction 250219) +02090 --250309) so that apply-141.8013 = -2477.57 enk enk = +141-80 kJ of 2477:57 - +141.80 x103 +24.77.97 =141800 2477.57 enk = 57.233 K = €57.233 #1 K=

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