Question

An object with the mass m= 2.0 kg hangs from a cord around a light pulley. The length of the cord between point P and the pulley is L= 2.0 m (Ignore the mass of the vertical section of the cord)

a) When the vibrator is set to a frequency of 160 Hz, a standing wave with six loops is formed. What must be the linear mass density of the cord in kg/m?

b) How many loops (if any) will result if m is changed to 72.0 kg (Enter 0 if no loops are formed)

c) How many loops (if any) will result if m is changed to 10kg? (Enter 0 if no loops are formed)

Answer 1

A5 Tamg (2kg ) (lomis) T=2ON mg mo l-am h=6 f = 16042 In ( ² )=L oooooo 6( )= 2m +372m 7 da 중계 v= FA V=(160H2) (m) ar=106.66741 as we know ve T le? TH M Mc 7 I 2ON (106.667 m/s)? Mal-7578x183 kg Im Ilinear mass density IT Ta mga (72 kg) (loms") = 720N m mg V= M 72ON 1-7578x103 kg/m v=640m's v= ft n ( 2 ) = 2 Gyomis: (160H2 ) um ha= 2l=2(2m)=um b um a na n (160 H2) (46) 64omis T n=1 lap T T-mg - Vorg) (10 m/s)100N m V= IOON mg 238.5mls 1.75788153 Kg/m ve fa h ( ² ) = 2385hls (160H2) (um -) → X 2(2m), um h h bu (160H2) (47) 238.5hls nshould be to integer #lhr 2.687 e ho standing ware is bely formed Thaol Scanned with CamScanner