Homework Answers
let the value of each division in galvanometer = i A
The current through ammeter I = 50i
when we applied a shunt resistance then Ig = 10i
shunt resistance S = 15 Ω
now for Galvanometer resistance G = ?
WE KNOW THAT
S= ( ( Ig) / (I -Ig) ) G
THEN
G=(( I -Ig )/ (Ig)S
Plugging the values in the formula
G = ( (50i-10i) / (10i) ) 15Ω
G = (4)(15Ω ) = 60Ω
G =60Ω
Galvanometer resistance is G = 60 Ω
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